1.

ज्ञात करे `int _(-pi//4)^(pi//4) x^(3) sin^(4) x dx `

Answer» माना कि ` f (x)= x^(3) sin^(4) x " "` …(1)
तो , ` f(-x) = (-x) ^(3) sin^(4) (-x) = -x^(3) (-sin x)^(4) = - x^(3) sin^(4) x = - f (x)`
अतः f(x) एक विषम फलन है ।
` :. int _(-pi//4)^(pi//4) f (x) dx = 0 `


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