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(K+4)x2+(k+1)x+1 |
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Answer» b2-4ac=0b= (k+1) ,... a= K+4,... c=,...b2-4ac=00= (k+1)2- 4(k+1) 1= k2+ 1 + 2k - 4k -1 =0=k2-2k=0= k(k-2) =0thus either K=0 or k= 2. What\'s the question?? It\'s incomplete question |
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