(k+9),(2k-1),(2k+7) is an ap find the consecutive number and find the

1.	(k+9),(2k-1),(2k+7) is an ap find the consecutive number and find the value of k
Answer» We know that difference between any two consecutive terms of an AP\xa0is equal{tex}\\therefore{a_2} - {a_1} = {a_3} - {a_2}{/tex}let\xa0{tex}a_1=(k+9), a_2=(2k-1), a_3=(2k+7){/tex}{tex} \\Rightarrow (2k - 1) - (k + 9) = (2k + 7) - (2k - 1){/tex}{tex} \\Rightarrow k - 10 = 8{/tex}{tex} \\Rightarrow k = 18{/tex}

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