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| 1. |
K(k-12)x²+2(k-12)x+2=0 |
| Answer» {tex}D = [2(k\xa0-12)]^2 - 4(k\xa0- 12)\\times 2{/tex}= 4(k -12)2 - 8(k - 12)For equal and real roots, D = 0{tex}\\Rightarrow{/tex}{tex}4(k\xa0- 12)^2 - 8(k - 12) = 0{/tex}{tex}\\Rightarrow{/tex}{tex}4(k - 12) (k - 12 - 2) = 0{/tex}{tex}\\Rightarrow{/tex}{tex}4(k - 12) (k\xa0- 14) = 0{/tex}{tex}\\Rightarrow{/tex}k\xa0=12 or k\xa0= 14{tex}\\because{/tex}a\xa0{tex}\\ne{/tex}\xa00\xa0{tex}\\Rightarrow{/tex}\xa0k\xa0{tex}\\ne{/tex}12;\xa0{tex}\\therefore{/tex} k = 14. | |