InterviewSolution
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InterviewSolution
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`k` के किस मान के लिए व्यंजक `p+1/4+sqrt(p)+k^(2)` एक पूर्ण वर्ग होगा? |
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Answer» Correct Answer - A `p+1/4+sqrt(p)+k^(2)` `implies p+sqrt(p)+(k^(2)+1/4)` `implies (sqrt(p))^(2)=2xx1/2xxsqrt(p)+(k^(2)+1/4)` `implies A^(2)+2xxAxxB+B^(2)` `implies A=sqrt(p)B^(2)=(k^(2)+1/4)` `B=1/2` `:. k^(2)+1/4=(1/2)^(2)` `k^(2)+1/4=1/4` `k^(2)=0` `k=0` |
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