Kx+2y=53x-4y=10

1.	Kx+2y=53x-4y=10
Answer» The given system of equations:\xa0kx + 2y = 5\xa0⇒ kx + 2y - 5 = 0 ….(i)\xa03x - 4y = 10\xa0⇒3x - 4y - 10 = 0 …(ii)\xa0These equations are of the forms:Thus for all real values of k other than −3/2 , the given system of equations will have a unique solution.\xa0(ii) For the given system of equations to have no solutions, we must have:

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