InterviewSolution
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InterviewSolution
| 1. |
Kx (x-2)+6=0 |
| Answer» We have, kx(x - 2) + 6 = 0{tex}\\Rightarrow k x^{2}-2 k x+6=0{/tex}........(1)We know that quadratic equation {tex}ax^2+bx+c=0{/tex},a≠0, has equal roots if its discriminant D is 0.D = 0\xa0{tex}\\Rightarrow{/tex}{tex}b^2-4ac=0{/tex}{tex}\\Rightarrow{/tex}4k2 - 4(k)6 = 0 [from given quad. equ.(1); a=k≠0, b= -2k, c= 6]{tex}\\Rightarrow{/tex}4k2 - 24k = 0\xa0{tex}\\Rightarrow{/tex}4k(k - 6) = 0 {tex}\\Rightarrow{/tex}k - 6 = 0 [ since, k≠0]{tex}\\Rightarrow{/tex}k = 6\xa0Hence the value of K is 6. | |