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Let A(1, 3), B(0, 0) and C(k, 0) be three points such that `ar(triangle ABC) =3` sq units. Find the value of k. |
Answer» We have `ar(triangle ABC) = 3` sq units `hArr (1)/(2) * |[1, 3, 1], [0, 0, 1], [k, 0, 1]| = +- hArr |[1, 3, 1],[0, 0, 1],[k, 0, 1] = +-6` `hArr (-1) * |[1, 3],[k, 0]|= +-6 hArr 3k = +-6 hArr k = +-2` Hence, `k = +-2` |
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