Let `D_(r) = |(a,2^(r),2^(16) -1),(b,3(4^(r)),2(14^(16) -1)),(c,7(8^(r)),4(8^(16) -1))|`, then the value of `Sigma_(k=1)^(16) D_(k)`, is

Let `D_(r) = |(a,2^(r),2^(16) -1),(b,3(4^(r)),2(14^(16) -1)),(c,7(8^(r

1.	Let `D_(r) = \|(a,2^(r),2^(16) -1),(b,3(4^(r)),2(14^(16) -1)),(c,7(8^(r)),4(8^(16) -1))\|`, then the value of `Sigma_(k=1)^(16) D_(k)`, is
Answer» Correct Answer - A `underset(k=1)overset(16)Sigma D_(k) = \|(a,underset(k=1)overset(16)Sigma 2^(k),2^(16) -1),(b,3 (underset(k=1)overset(16)Sigma 4^(k)),2(4^(16) -1)),(c,7 (underset(k=1)overset(16)Sigma 8^(k)),4(8^(16) -1))\|` `rArr underset(k=1)overset(16)Sigma D_(k) \|(a,2((2^(16) -1)/(2 -1)),2^(16) -1),(b,3xx 4 ((4^(16) -1)/(4 -1)),2(4^(16) -1)),(c,7xx 8 ((8^(16) -1)/(8 -1)),4(8^(16) -1))\|` `rArr underset(k=1)overset(16)Sigma D_(k) =2 \|(a,(2^(16) -1),(2^(16) -1)),(b,2(4^(16) 1),2(4^(16) -1)),(c,4(8^(16) -1),4(8^(16) -1))\| [("Taking 2 common"),(" from " C_(2))]` `rArr underset(k=1)overset(16)Sigma D_(k) = 2 xx 0 = 0`