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Let`f(x)={(1-cos4x)/(x^2a,),ifx0,ifx=0`Determine the value of `a`so that `f(x)`is continuous at `x=0.` |
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Answer» LHL=`f(0^-)` `f(x) = (1- cos 4x)/x^2` `= (2sin^2 2x)/(x^2)` `=> 2(sin2x)/(2x) *(sin2x)/(2x) *2*2= 8` `sqrtx/(sqrt(16 +sqrtx) - 4) xx (sqrt(16+ sqrtx))/(sqrt(16 + sqrtx) + 4)` `=(sqrtx( sqrt(16 + sqrtx) + 4))/(16 + sqrtx - 16)` `= sqrt(16 + sqrtx) + 4` `= sqrt16 + 4 = 4 + 4 = 8` so,`a=8` Answer |
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