1.

Let`f(x)={(1-cos4x)/(x^2a,),ifx0,ifx=0`Determine the value of `a`so that `f(x)`is continuous at `x=0.`

Answer» LHL=`f(0^-)`
`f(x) = (1- cos 4x)/x^2`
`= (2sin^2 2x)/(x^2)`
`=> 2(sin2x)/(2x) *(sin2x)/(2x) *2*2= 8`
`sqrtx/(sqrt(16 +sqrtx) - 4) xx (sqrt(16+ sqrtx))/(sqrt(16 + sqrtx) + 4)`
`=(sqrtx( sqrt(16 + sqrtx) + 4))/(16 + sqrtx - 16)`
`= sqrt(16 + sqrtx) + 4`
`= sqrt16 + 4 = 4 + 4 = 8`
so,`a=8`
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