Let x-1, x-4 and x-7 are in AP find the value of x

1.	Let x-1, x-4 and x-7 are in AP find the value of x
Answer» If x-1, x-4 and x-7 are in APthen x-4 will be average of x-1 and x-7[(x-1)+(x-7)]*1/2=x-42x-1-7=2(x-4)2x-8=2x-82x-2x=-8+80=0Hence there is no solutionStatement in your question is not a question this shows thatx-1, x-4 and x-7 are in AP for all real values of xSo x =.-infinite........-5,-4,-3,-2,-1,0,1,2,3.......................infinite\xa0

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