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Let `|(x,2,x),(x^(2),x,6),(x,x,6)| = ax^(4) + bx^(3) + cx^(2) + dx + e` Then, the value of `5a + 4b + 3c + 2d + e` is equal to |
Answer» Correct Answer - D We have, `|(x,2,x),(x^(2),x,6),(x,x,6)|` `= |(x,2,x),(x^(2),x,6),(x -x^(2),0,0)| " " ["Applying " R_(3) rarr R_(3) - R_(2)]` `= (x -x^(2)) (12 -x^(2))` `= 12 x - x^(3) - 12x^(2) + x^(4)` `:. a =1, b = -1, c = -12, d = 12 and e = 0` `:. 5a + 4b + 3c + 2d + e = 5 - 4 - 36 + 24 + 0 = -11` |
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