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Light of wavelength `lambda` is incident on a slit of width d and distance between screen and slit is D. Then width of maxima and width of slit will be equal if D is ––A. `(d^(2))/(lambda)`B. `(2d)/(lambda)`C. `(2d^(2))/(lambda)`D. `(d^(2))/(2lambda)` |
Answer» Correct Answer - D |
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