

InterviewSolution
Saved Bookmarks
1. |
`"log" ("log"x), x gt 1` |
Answer» `"Let"y = "log" ("log"x)` `rArr (dy)/(dx) = (d)/(dx) "log" ("log"x)` `=(1)/("log"x)*(d)/(dx)"log"x = (1)/( x "log" x)` |
|