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Mark the correct alternative in the following : The value of the determinant \(\begin{vmatrix}a-b &b+c & a \\[0.3em]b-a & c+a & b \\[0.3em]c-a & a+b & c\end{vmatrix}\) isA. a3 + b3 + c3 B. 3bc C. a3 + b3 + c3 – 3abc D. none of these |
Answer» Correct answer : (D) Assume a = 1,b = 2, c = 3 (put in determinant) Δ = \(\begin{vmatrix}-1 & 5& 1 \\[0.3em]1 & 4 &2 \\[0.3em]2 &3&3\end{vmatrix}\) ∆ =[-1(12 - 6) - 5(3 - 4)+1(3 - 6)] ∆ =- 4 Put a = 1,b = 2, c = 3 in option A,B,C,D ANSWER = D (none of these ) |
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