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मूल्यांकन कीजिएः `int_(0)^(pi) sin^(3)xdx` |
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Answer» `underset(0)overset(pi)int sin^(3)xdx` `underset(0)overset(pi)int (3sin x-sin 3x)/(4)dx, [therefore sin 3x=3sin x-4sin^(3)x]` `=1/4underset(0)oversetpiint (3 sin x- sin 3x)dx` `=1/4[-3 cosx+(cos 3x)/(3)]_(0)^(pi)` `=1/4[{-3 cos pi+(cos 3x)/(3)} -{-3 cos 0+(cos 0)/(3)}` `=1/4[{-3xx(-1)+((-1))/(3)}-{-3+1/3}]` `=1/4[(3-1/3)-(-3+1/3)]` `=1/4 (6-2/3)=1/4xx16/3=4/3` |
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