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निम्न समीकरण को हल कीजिए - `cos^(2) theta - sin theta cos theta - 1/2 = 0` |
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Answer» दिया है - `cos^(2) theta - sin theta cos theta - 1/2 = 0` `rArr 2 cos^(2) theta - 2 sin theta cos theta - 1 = 0` `rArr (2 cos^(2) theta-1) - 2 sin theta cos theta = 0` `rArr cos 2 theta - sin 2 theta = 0` `rArr tan 2 theta = 1 = tan . pi/4` `rArr 2 theta = n pi + pi/4` `rArr theta = (n pi)/2 + pi/8` |
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