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Nitesh wants to make a wine solution of 50% concentration by mixing 5L of wine solution with 2L of another wine solution of 70% concentration but by mistake he used 2L of water in place of 2L wine solution of 70% concentration. Now how much wine solution of 60% concentration be mixed with the solution formed by mistake to get wine solution of 50% concentration.1). 12L2). 14L3). 16L4). 18L |
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Answer» Let concentration 5L of wine solution be x% ⇒ 5 × (x/100) + 2 × (70/100) = 7 × (50/100) ⇒ x = 42 ∴ Concentration of 5L of wine solution is 42% Let concentration of solution formed by mixing 5L of wine solution of 42% with WATER be y% ⇒ 5 × (42/100) + 2 × (0/100) = 7 × (y/100) ⇒ y = 30 Let z L of wine solution of 60% concentration is MIXED with wine solution of 30% concentration formed by mixing water and 5l of wine solution ⇒ 7 × (30/100) + z × (60/100) = (7 + z) × (50/100) ⇒ 210 + 60z = 350 + 50z ⇒ z = 14 ∴ 14L of wine solution of 60% concentration is mixed to FORM wine solution of 50% concentration. |
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