1.

Nitesh wants to make a wine solution of 50% concentration by mixing 5L of wine solution with 2L of another wine solution of 70% concentration but by mistake he used 2L of water in place of 2L wine solution of 70% concentration. Now how much wine solution of 60% concentration be mixed with the solution formed by mistake to get wine solution of 50% concentration.1). 12L2). 14L3). 16L4). 18L

Answer»

Let concentration 5L of wine solution be x%

⇒ 5 × (x/100) + 2 × (70/100) = 7 × (50/100)

⇒ x = 42

∴ Concentration of 5L of wine solution is 42%

Let concentration of solution formed by mixing 5L of wine solution of 42% with WATER be y%

⇒ 5 × (42/100) + 2 × (0/100) = 7 × (y/100)

⇒ y = 30

Let z L of wine solution of 60% concentration is MIXED with wine solution of 30% concentration formed by mixing water and 5l of wine solution

⇒ 7 × (30/100) + z × (60/100) = (7 + z) × (50/100)

⇒ 210 + 60z = 350 + 50z

⇒ z = 14

∴ 14L of wine solution of 60% concentration is mixed to FORM wine solution of 50% concentration.


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