Number points of discontinuity of `f(x)=tan^2x- sec^2 x` in `(0,2pi)` – InterviewSolution

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1.	Number points of discontinuity of `f(x)=tan^2x- sec^2 x` in `(0,2pi)` is
Answer» `f(x) = tan^2x - sec^2x = sin^2x/cos^2x - 1/cos^2x` We know, at `x = pi/2` and `x = (3pi)/2`, value of `cos x` will be `0`. So, given function will not be defined and not continuous at these points. So, number of points of discontinuity will be `2`.

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