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O.2x+0.3y=1.30.4x+0.5y=2.3

Answer» 0.2x\xa0+ 0.3y\xa0= 1.3 ...\xa0(i)0.4x\xa0+ 0.5y\xa0= 2.3 ...\xa0(ii)Solving equation\xa0(i), we get0.2x\xa0= 1.3 – 0.3yDividing by 0.2, we getx\xa0= 1.3/0.2 - 0.3/0.2x\xa0= 6.5 – 1.5\xa0yPutting the value in equation\xa0(ii), we get0.4x\xa0+ 0.5y\xa0= 2.3(6.5 – 1.5y) ×\xa00.4x\xa0+ 0.5y\xa0= 2.32.6 – 0.6y\xa0+ 0.5y\xa0= 2.3-0.1y\xa0= 2.3 – 2.6y\xa0= -0.3/-0.1y\xa0= 3Putting this value in equation\xa0(i)\xa0we get x\xa0= 2\tx\xa0= 2 and\xa0y\xa0= 3\t


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