1.

Obain all zeroes of 2x^4+x cube-14x square -19x-6 if two of its zeroes are -2 & -1

Answer» if -2 and -1 are zeros of\xa0f(x) = 2x4 + x3 - 14x2 - 19x - 6x+2 and x+1 are factors of f(x)So (x + 2)(x + 1) = x2 + x + 2x + 2 = x2 + 3x + 2 is a factor of f(x)On long division of f(x) by\xa0x2 + 3x + 2 we getf(x) = 2x4 + x3 - 14x2 - 19x - 6 = (2x2 - 5x - 3)(x2 + 3x + 2)= (2x + 1)(x - 3)(x + 2)(x + 1)Therefore, zeroes of the polynomial = {tex}\\frac{{ - 1}}{2}{/tex}, 3, -2, -1.


Discussion

No Comment Found