1.

Obtain all other zeroes of 2x(cube)+5x(square)-28x_15,if one of its zeroes is 3

Answer» Here polynomial is 2x^3+5x^2-28x-15One zero=3Therefore it\'s first factor is (x-3)Now, divide the polynomial from it\'s first factor.We obtain the quotient (2x^2+11x+5) and remainder=0Now, polynomial = 1st factor + QuotientNow factorise it\'s quotient(2x^2+11x+5)=2x^2+10x+1x+5 = 2x(x+5)+1(x+5) = (x+5)(2x+1)Now it\'s factors are minus 5 and minus 1÷2 .
-4.5 and -0.5


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