obtain all the zeroes of the polynomial x4+6x3+x2-24x-20, if two zeroe

1.	obtain all the zeroes of the polynomial x4+6x3+x2-24x-20, if two zeroes are 2 and -5\xa0
Answer» ACQ, Factors are (x - 2) and (x + 5) => (x - 2)(x + 5) => x2+3x-10on dividing given polynomial by x2+3x-10, we get the quotient x2+3x+2Therefore, x4+6x3+x2-24x-20 = (x2+3x-10)(x2+3x+2)=> x4+6x3+x2-24x-20 = (x2+3x-10)(x2+2x+x+2)=> x4+6x3+x2-24x-20 = (x2+3x-10)[x(x+2)+1(x+2)]=> x4+6x3+x2-24x-20 = (x2+3x-10)(x+2)(x+1)Therefore, all other zeroes are -2 and -1.

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