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Obtain all the zeros of f(x)=x^3+13x^2+3x+20is one of its zeroes is -2 |
| Answer» Here\xa0f(x) = x3 + 13x2 + 32x + 20-2 is a zero of f(x), so x+2 will be factor of f(x)On long division of f(x) by x+2 we getSo, f(x) = x3 + 13x2 + 32x + 20= (x2 + 11x + 10)(x + 2)= (x2 + 10x + x + 10)(x + 2)= (x + 10)(x + 1)(x + 2)Hence f(x)=0 if x+10 =0 or x+1=0 or x+2=0Therefore, the zeroes of the polynomial are -1, -10, -2. | |