Obtain the equation for critical angle.

1.	Obtain the equation for critical angle.
Answer» Snell’s law in the product form, equation for critical angle incidence becomes, n₁ sini i_c = n₂ sin 90° n₁ sini i_c = n₂ (∵ sin 90° = 1) sini i_c = (\(\frac{n_2}{n_1}\)) Here, n₁ > n₂ If the rarer medium is air, then its refractive index is 1 and can be taken as n itself, i.e. (n₂ = 1) and (n₁ = n). sini i_c = \(\frac{1}{n}\) or i_c= sin^-1(\(\frac{1}{n}\))

Answer»

Snell’s law in the product form, equation for critical angle incidence becomes, n₁ sini i_c = n₂ sin 90°

n₁ sini i_c = n₂ (∵ sin 90° = 1)

sini i_c = (\(\frac{n_2}{n_1}\))

Here, n₁ > n₂

If the rarer medium is air, then its refractive index is 1 and can be taken as n itself, i.e. (n₂ = 1) and (n₁ = n).

sini i_c = \(\frac{1}{n}\) or i_c= sin^-1(\(\frac{1}{n}\))

Discussion

No Comment Found

Related InterviewSolutions

Red light of wavelength `6500 Å` from a distant source falls on a slit `0.50 mm` wide. Calculate the distance between first two dark bands on each side of central bright band in the diffraction pattern observed on a screen placed `1.8 m` from the slit.
The ratio of the intensity at the centre of a bright fringe to the intensity at a point one-quarter of the distance between two fringe from the centre is
The ratio of the intensity at the centre of a bright fringe to the intensity at a point one-quarter of the distance between two fringe from the centre isA. `2`B. `1//2`C. `4`D. `16`
Among the two interfering monochromatic sources A and B, A is ahead of B in phase by `66^@`. If the observation be taken from point P, such that `PB-PA=lambda//4`. Then the phase difference between the waves from A and B reaching P isA. `156^(@)`B. `140^(@)`C. `136^(@)`D. `126^(@)`
The radius of curvature of curved surface of a thin plano-convex lens is `10 cm` and the refractive index is `1.5`. If the plano surface is silvered, then the focal length will be.A. 15 cmB. 20 cmC. 5 cmD. 10 cm
Calculate the resolving power of a microscope with cone angle of light falling on the objective equal to `60^(@)`. Take `lambda = 600 nm mu` for air `= 1`.
The diameter of the pupil of human eye is about `2 mm`. Human eye is most sensitive to the wavelength `555 nm`. Find the limit of resolution of human eye.
Assume that light of wavelength `6000 Å` is coming from a star. What is the limit of resolution of a telescope whose objective has a diameter of 100 inch ? (NCERT Solved example)
A central fringe of interference pattern produced by light of wavelength `6000 Å` is shifted to the position of 5th bright fringe by introducing thin film of `mu = 1.5`. Calculate thickness of the film.
Laser light of wavelength `630 nm` incident on a pair of slits produces an interference pattern where bright fringes are separated by `8.1 mm`. Another light produces the interference pattern, where the bright fringes are separated by `7.2 mm`. Calculate the wavelength of second light.

Obtain the equation for critical angle.

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment