Saved Bookmarks
| 1. |
Out of supplementary angles larger one is 18°greater than the smaller one .find both angle |
| Answer» Let the supplementary angles be x°\xa0and y° (x° > y°) Now, x° + y° = 180 ........ (i)\xa0and x° - y° = 18 ..(ii)From eqn. (ii), y° = x° - 18 ...(iii)Put (iii) in (i)x° + x° - 18° = 180°⇒ 2x° = 180° + 18°⇒ 2x° = 198°⇒ x° = 99°On substituting\xa0{tex}x ^ { \\circ } = 99 ^ { \\circ }{/tex}\xa0in eqn. (iii),{tex}y ^ { \\circ } = 99 ^ { \\circ } - 18 ^ { \\circ } = 81 ^ { \\circ }{/tex}{tex}\\therefore {/tex}{tex}y ^ { \\circ } = 81 ^ { \\circ }{/tex}Hence, the angles are\xa0{tex}99 ^ { \\circ } \\text { and } 81 ^ { \\circ }{/tex} | |