P(x)=ax^2 + bx + c. If a + b + c = 0, then find one of its zero

1.	P(x)=ax^2 + bx + c. If a + b + c = 0, then find one of its zero
Answer» It is given that a + b\xa0+ c = 0We have function p(x) = ax2 + bx + cUsing remainder theorem by putting x=1 we getp(1) = a {tex}\\times{/tex}\xa012+ b\xa0+ c= a + b\xa0+c = 0 (given){tex}\\therefore{/tex}\xa0x = 1 is one zero

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