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Particles of masses 1 kg and 3 kg are at (2i+5j+13k) m and (-6i+4j-2k) m. What is the position of their centre of mass?(a) 1/4 (-16i + 17j + 7k) m(b) 1/4 (-8i + 17j + 7k) m(c) 1/4 (-6i + 17j + 7k) m(d) 1/4 (-6i + 17j + 5k) mI had been asked this question in semester exam.I need to ask this question from System of Particles in chapter System of Particles and Rotational Motion of Physics – Class 11

Answer»

Correct ANSWER is (a) 1/4 (-16i + 17j + 7k) m

For explanation: SUM of masses = 1 + 3 = 4

x-coordinate;

(1*2-3*6)/4 = -16/4

y-coordinate;

(1*5 + 3*4)/4 = 17/4

z-coordinate;

(1*13-3*2)/4 = 7/4

Position of CENTRE of MASS = 1/4 (-6i + 17j + 5k) m.



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