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Patterned baldness is a sex influenced trait more expressed in a male. If b+ is normal allele making non-bald phenotype and b is mutant leading to bald phenotype, for a cross between a bald mother and normal father, what is the probability of a bald son?(a) 0(b) 1/4(c) 1/2(d) 1This question was posed to me at a job interview.I'm obligated to ask this question of Sex Influenced Traits and Sex Limited Traits in section Chromosomes and Sex Determination of Cytogenetics

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Right option is (d) 1

To explain: Baldness is a sex influenced trait, so the mother is certainly B/b and the father is b+,b+. So, the son will get at least one baldness allele from the mother. Heterozygous male EXPRESSES the sex influenced trait; hence the son will DEFINITELY be BALD.



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