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Please explain BPT THOEREM

Answer» Theorm : In a right triangle, the sq. Of the hyp. is equal to the sum of the sq. Of the other two sides.Proof : In a right ∆ ABC right angled at B.Prove : AC ka 2 = AB ka 2 + BC ka 2 BD is parrallel to AC∆ADB ~ ∆ ABC AD/AB = AB/AC ( side are propotional)AD.AC = AB ka 2∆BDC ~∆ABCCD/BC =BC / ACCD. AC = BC ka 2 AD.AC. + CD.AC = AB ka 2 + BC ka 2AC (AD + CD) = AB ka 2 + BC ka 2AC.AC. = AB ka 2 + BC ka 2AC ka 2 = AB ka 2 + BC ka 2


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