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Plzzzz someone tell me the value of all trigonometric ratios. |
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Answer» The\xa0Trigonometry Ratios\xa0of the angle θ in the triangle APM are defined as follows.Opposite over Hypotenuse – Sin,\xa0Adjacent Over Hypotenuse – Cos, Opposite over Adjacent – Tan, Hypotenuse over Opposite – Cosec, Hypotenuse Over Adjacent – Sec and Adjacent over Opposite – Cotangent,The ratios defined above are abbreviated as sin θ, cos θ, tan θ, cosec θ, sec θ and cot θ respectively. Note that the ratios\xa0cosec θ, sec θ and cot θ\xa0are respectively, the reciprocals of the ratios sin θ, cos θ and tan θ. So, the trigonometric ratios of an acute angle in a right triangle express the relationship between the angle and the length of its sides.Opposite of Sin: CosecantOpposite of Cos:\xa0SecantOpposite of Tan: CotangentOpposite of Cosecant:\xa0SinOpposite of Cotangent: TanOpposite of Secant: CosecantTrig Mnemonics –\xa0\xa0Some\xa0People\xa0Have,\xa0Curly\xa0Black\xa0Hair\xa0Through\xa0Proper\xa0Brushing.Here,\xa0Some\xa0People\xa0Have is for\tSin θ=\xa0Perpendicular/\xa0Hypotenuse.Curly\xa0Black\xa0Hair is for\tCos θ=\xa0Base/\xa0Hypotenuse.Through\xa0Proper\xa0Brushing is for\tTan θ=\xa0Perpendicular/BaseTrigonometric Ratios of Some Specific AnglesWe already know about isosceles right angle triangle and right angle triangle with angles 30º, 60º and 90º.Can we find sin 30º or tan 60º or cos 45º etc. with the help of these triangles?Does sin 0º or cos 0º exist? |
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