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Preeti reached the metro station and found that the escalator was not working. She walked up the stationary escalator in time `t_1`. On other days, if the remains stationary on the moving escalator, then the escalator takes her up in time `t_2`. The time taken by her to walk up on the moving escalator will be :A. `(t_1 t_2)/(t_2 - t_1)`B. `(t_1 t_2)/(t_2 + t_1)`C. `t_1 - t_2`D. `(t_1 + t_2)/(2)` |
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Answer» Correct Answer - B Velocity of Preeti w.r.t. elevator `= (l)/(t_1)` Velocity of elevator w.r.t. ground `= (l)/(t_2)` Then velocity of girl w.r.t. ground `vec v_("preeti") = vecv_("preeti,elevator") + vecv_("elevator")` `(l)/(t) = (l)/(t_1) + (l)/(t_2)` `rArr t = (l)/(l/(t_1) +(l)/(t_2)) =(t_1 t_2)/(t_1 + t_2)`. |
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