Saved Bookmarks
| 1. |
Proof of pyathagoras theoram |
|
Answer» √16=℅§Π μ Ω ♣♠♪♥♦₱↓∞≈‰»›»«‹«№₱–—_·±<]¿¡››»‡†★…………/ In a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.Given: -\xa0\xa0is a right angle of\xa0To Prove:-\xa0Construction:-\xa0is drawnProof:- In\xa0Or, AB2\xa0= AC X AD ---------------------(i)Similarly\xa0Or, BC2\xa0= AC X CD ---------------------(ii)Adding (i) and (ii) we getAB2\xa0+ BC2\xa0= AC X AD + AC X CD= AC X (AD + CD)= AC X AC= AC2Or, AC2\xa0= AB2\xa0+ BC2 |
|