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Proove that (6+√5) is irrational

Answer» Let 6+√5 is a rational number So 6+√5= p÷ q √5=p÷q-6 √5=p-6q÷ q We know that √5 is an irrational number so p-6q÷q but we know that p-6q÷q is an rational number So that it contracdict our form that 6+√5 is an irrational number
This shows that 6+√5 is irrational
Let 6+√5 be rational6+√5=a/b (a & b are co-primes)√5=a/b -6LCM√5=a-6b/bIrrational not = rational


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