Proove that root2 is an irrational no.

1.	Proove that root2 is an irrational no.
Answer» Given √2 is irrational number.Let √2 = a / b wher a,b are integers b ≠ 0we also suppose that a / b is written in the simplest formNow √2 = a / b ⇒ 2 = a2\xa0/ b2\xa0⇒ 2b2\xa0= a2∴ 2b2\xa0is divisible by 2⇒ a2\xa0is divisible by 2 ⇒ a is divisible by 2 ∴ let a = 2ca2\xa0= 4c2\xa0⇒ 2b2\xa0= 4c2\xa0⇒\xa0b2\xa0= 2c2∴ 2c2 is divisible by 2∴ b2 is divisible by 2∴ b is divisible by 2∴a are b are divisible by 2 .this contradicts our supposition that a/b is written in the simplest formHence our supposition is wrong∴ √2 is irrational number??

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