Prove 3√2 is irrational

1.	Prove 3√2 is irrational
Answer» Prove :Let 3+√2 is an rational number.. such that 3+√2 = a/b ,where a and b are integers and b is not equal to zero ..therefore, 3 + √2 = a/b√2 = a/b -3√2 = (3b-a) /btherefore, √2 = (3b - a)/b is rational as a, b and 3 are integers.. It means that √2 is rational.... But this contradicts the fact that √2 is irrational.. So, it concludes that 3+√2 is irrational.. hence proved..

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