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Prove root 3 as irrational

Answer» Let √3 be a rational number then it can be written in the form of a/ b, b≠0 and a and b are co prime numbers . √3=a/b , now squaring on both sides gives 3=a²/b²........... 3b²=a² it means a² is divisible by 3 , so a is also divisible by 3 ....... Let a=3c now squaring on both sides gives a²=9c² . putting value of a².... 3b²=9c² , it gives us b²=3c² .. it means b² is divisible by 3 so b is also divisible by 3 ..... Therefore our assumption is wrong . They have a common factor as 3 . So √3 is an irrational number . Hence proved
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