Prove sec ∅√(1-sin2∅)= 1

1.	Prove sec ∅√(1-sin2∅)= 1
Answer» LHS= secA√(1-sin²A) [using identity cos²A=1-sin²A] = secA√cos²A = secA.cosA = 1/cosA.cosA =1 = RHSHence proved. Here LHS=secA√(1-sin²A)Since 1-sin²A=cos²A and secA=1/cosA=1/cosA√cos²A=1/cosA *cosA=1=RHSHERE I TAKE A FOR THITHA

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