prove :- sinA-2sin cube A / 2cos cube A-cosA= tan A

1.	prove :- sinA-2sin cube A / 2cos cube A-cosA= tan A
Answer» L.H.S.= sinA-2sin cube A / 2cos cube A - cosA =sinA(1-2sin square A) / cosA(2cos square A -1) =tanA[1 - 2sin square A / 2(1 - sin square A) - 1] = tanA[1 - 2sin square A / 2 - 2sin square A - 1] = tanA[1-2sin square A / 1-2sin square A] = tanA×1 = tanA = R.H.S. Ncert is useful Ncert .. chapter trignometry ka exercise 8.4 question 5th ka (VII) Ncert ka h ex 8.4

Discussion