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Prove sinA-2sincubeA÷2coscubeA-cosA=tan A |
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Answer» Take LHS...SinA-2sin^3A/2cos^3A-cosA...SinA(1-2sin^2A)/cosA(2cos^2A-1) 【Sin^2A= 1- Cos^2A】..SinA(1-2+2cos^2A)/cosA(2cos^2A-1)....SinA(cos^2A-1)/cos(2cos^2A-1)...Then cos^2A- 1will be canceled out....SinA/cosA= tanALHS=RHS Hence prove |
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