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Prove that 1+cosa/Sina=Sina/1-cosa

Answer» {tex}\\frac{{1+cosA}}{sinA}{/tex}={tex}\\frac{{(1+cosA)(1-cosA)}}{sinA(1-cosA)}{/tex}={tex}\\frac{{1-cos²A}}{sinA(1-cosA)}{/tex}={tex}\\frac{{sin²A}}{sinA(1-cosA)}{/tex}={tex}\\frac{{sinA}}{(1-cosA)}{/tex}


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