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Prove that 2-3Root 5

Answer» Let, 2-3√5 be a rational number.2-3√3=a/bWhere \'a\' and \'b\' are coprimes-3√3=a/b-2-3√3=a-2b/b √3=a-2b/b×(-3) √3=a-2b/-3b √3=(integer)-2(integer)/-3(integer) √3=rational numberBut,comtradiction √3 is a irrational number.Thus, Our assumption is wrong.Therefore, 2-3√5 is a irrational number.


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