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Prove that √2 is an irrational no.

Answer» Contradict that √2 is rational and√2 =a/b then square both sides , 2b2=a2 so a is divisible bt two then let a=2c where c is some integer . Now, 2b2=(2c)2= 2b2=4ç2 So,b2 = 2c2 and b is also divisible by 2 .since a and b are divisible by two , therefore they have common factor 2


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