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Prove that √3 is irrational. |
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Answer» I have alredy given answer for this question Let us take root 3 as rational number The rational number is of the form a/b where a, b are integers and b not equal to zero, such that a is equal to root 3 bA square is equal to 3 b square Therefore a square is divisible by 3That implies A is also divisible by 3Let us take b is equal to 3kA square is equal to 3 into 3 k square3a squareis equal to 3 into 3 k squareTherefore b square is divisible by 3That implies B is also divisible by 3A and b has a common factor 3Bat this contradicts to the fact that a/b is irrational That implies root 3 is irrational |
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