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Prove that 3+root 7 is an irrational number

Answer» Let us assume to the contrary that root 3 + root 7 is rational Now 3+ root 7 =p/QRoot 7 = p/Q -3Root 7 is p-3q/Q Now p= integer and q= integer so Integer-3integer /integer is rational no.So 3+ root7is rationalBut this contradicts that fact that 3+root 7 is irrational Our assumption is wrong So 3+root 7 is irrational
Hmm
Correct
Rs agrwall kaa first chapter dekh k sikhle bhai


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