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Prove that 5 is a irrational number. |
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Answer» Let us assume √5 as rational number √5 =a/b where a and b are Co primesSquaring both sides5 =a2/b25b2 =a2 5 divides a2 5 divides a Let a = 5c 5= 25c2/b25 divides b2 5divides b Therefore a nb have common factor as 5But this this lead to to contradiction because a nb have no common factor other than 1 Therefore our assumption is wrong √5 is irrational See u any 10 th class book its a simple yrr... |
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