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Prove that ✓5 is irrational number

Answer» You should first have to assume that √5 is rational√5=p/q that is p=√5qSquaring on both side p2=5q2 P2/5=q2:.P2is divisible by 5:.p is also divisible by 5P=5 are for some integer=rSquaring on both side p2= 25r2Then it became 25r2=5q2r2=5q/25r2=q2/5Again q2 is divisible by 5And q is also divisible by 5Then we have to write reason that 5 is coom factor and p&q are co-prime. This codradiction has arise because of our incorrect assumption so we consider that root 5 is irrational number .


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