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| 1. |
Prove that √6+√2 is irrational |
| Answer» Let take that 6 + √2 is a rational number.So we can write this number as6 + √2 = a/bHere a and b are two co-prime number and b is not equal to 0Subtract 6 both side we get√2 = a/b – 6√2 = (a-6b)/bHere a and b are an integer so (a-6b)/b is a rational number so √2 should be a rational number But √2 is an irrational number so it is contradictingHence result is 6 + √2 is a irrational number | |