1.

Prove that 6-root3 is irrational.

Answer» Yes
Let 6√3 be a rational number , so it can be written in the form of a/b where b≠0 and a and b are co prime numbers ......... .......... 6√3=a/b .. now √3 = a/b-6 , as we know that √3 is an irrational number , therefore our assumption is wrong. Hence due to contradiction 6√3 is an irrational number .hence proved .


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