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Prove that 6n cannot end with digit 0 |
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Answer» If any number ends with the digit 0, it should be divisible by 10 or in other words, it will also be divisible by 2 and 5 as 10 = 2 × 5Prime factorisation of 6n = (2 ×3)nIt can be observed that 5 is not in the prime factorisation of 6n.Hence, for any value of n, 6n will not be divisible by 5.Therefore, 6n cannot end with the digit 0 for any natural number n. (2×3)n So , it is not end with 0The factors are in the form of 2n and 3n. Because it has no 5 as its factor |
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